Question

The temperature at noon was –6.5⁰C. The temperature rose 3.5⁰C from noon to 1 p.m. The temperature increased t degrees centigrade from 1 p.m. to 2 p.m. The temperature at 2 p.m. was –12⁰C.

Which equation can be used to solve for t?

A.
–6.5 – 3.5 – t = –12

B.
–6.5 + 3.5 + t = –12

C.
–6.5 + 3.5 – t = –12

D.
–6.5 – 3.5 + t = –12

Answer 1

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Answer 2

B. The temperature rose 3.5 from -6.5, then it increased t degrees. When it increases you have to add.

Answer 3

^^

Answer 4

thank you! :)

Answer 5

You're welcome!