Question

The area of a rectangle is
54 ft2
, and the length of the rectangle is
3 ft
more than twice the width.

Answer 1

@iambatman @iambatman @aum @dareintheren @PurplePanda312 @Race100

Answer 2

Find the dimensions of the rectangle.

Answer 3

@theEric @tkhunny @Teddyiswatshecallsme @Rockiee @girlover @ash2326

Answer 4

@myininaya

Answer 5

@PurplePanda312

Answer 6

I don't know sorry.

Answer 7

@hartnn @ash2326

Answer 8

@fateal

Answer 9

lol call @Dark_Riddles this is a goo riddle :')

Answer 10

@Dark_Riddles

Answer 11

@Dark_Riddles

Answer 12

c

Answer 13

can you help me

Answer 14

The area of a rectangle is
54 ft2
, and the length of the rectangle is
3 ft
more than twice the width.

Answer 15

Find the dimensions of the rectangle.

Answer 16

Well, I'll tell you one thing, this house is going to be crooked as crap.

Answer 17

lol

Answer 18

how do I put this into an equation

Answer 19

are you confuse as I

Answer 20

is this right X^2+3x-54=0 @Dark_Riddles

Answer 21

Well, using "X" is probably a bad idea.
Changing to "x" int eh middle of the problem is another bad idea.

Super Big Clue that will Change Your Life --- WRITE DOWN DEFINITIONS!!

L = Length
W = Width

L*W = Area

"area of a rectangle is 54 ft2"

L*W = 54

" length of the rectangle is 3 ft more than twice the width."

L = 3 + 2W

Substitute for L

(3+2W)*W = 54

2W^2 + 3W - 54 = 0

Notice how every step of the way you can FOLLOW what is happening. This is what you should be doing.