Question

Find the equation of the tangent line to the curve y=sec(x)-2cos(x) at the point (pi/3,1).

Answer 1

first find slope of tangent
that will be = dy/dx

Answer 2

dy/dx=d(secx-2cosx)/dx

Answer 3

and after finding it put these (pi/3,1) in the result of dy/dx

Answer 4

calculate it n tell me the ans ..i assist you in this plsss try

Answer 5

y=sec(x)tan(x)-2sin(x)

Answer 6

i dont get how to put this in to y=mx+b