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Mathematics 9 Online
OpenStudy (anonymous):

Find the absolute extrema of the function on the closed interval. g(t) = t^2/t^2 + 2, [−1, 1]

OpenStudy (loser66):

take first derivative, let it=0, solve for t. find f(t's) and f(-1) , f(1) compare the values of those f , the greatest is absolute max, the smallest is absolute min

OpenStudy (anonymous):

yeah, i got it...i did a small calculation error, but thanks

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