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Find the length of the shaft if the following is true. A = 3/16 in B = 6 7/8 in C= 1 3/8 in ? in
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\[Length ~of~shaft=\frac{ 3 }{ 16 }+6\frac{ 7 }{ 8 }+1\frac{ 3 }{ 8 }=\frac{ 3 }{ 16 }+\frac{ 55 }{ 8 }+\frac{ 11 }{ 8 }=?\]
69/32
am I right?
nope its suppose to be 135/16
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thank you :)
my pleasure :) do you understand how that suppose to be 135/16
no not really
|dw:1411916371176:dw| denominator how many times multiply to get 16 so 16 times 1 is = 16 8x2=16 so multiply 55 by 2 which is =110 last denominator 8 x2 is 16 so again 2 multiply 11 which is 22 so add all 16+110+22=??
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