an object is released from rest on a planet that has no atmosphere. the object falls freely for 5.82 m on the first second. what is the magnitude of the acceleration due to gravity on the planet

Question

anonymous · Answer

11.64m/s^2
given..u=0m/s,
          n=1sec,
          S(n)=5.82m,
          a=+g(since, downward motion)
from S(n)=u+a(n-0.5);
         5.82=0+g(1-0.5)
         5.82=g(0.5)
         g=5.82/0.5
         g=11.64m/s^2
hope this helps you...cheers!!!