A mortar crew is positioned near the top of a steep hill. Enemy forces are charging up the hill and it is necessary for the crew to spring into action. Angling the mortar at an angle of θ = 57.0 (as shown), the crew fires the shell at a muzzle velocity of 224 feet per second. How far down the hill does the shell strike if the hill subtends an angle φ = 33.0 from the horizontal? (Ignore air friction.)

Question

anonymous · Answer

"as shown"
Do you have the picture?