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Trigonometry 12 Online
OpenStudy (anonymous):

cot^2x=1 what is x

geerky42 (geerky42):

\(\cot^2x = \dfrac{\cos^2x}{\sin^2x}\) So \(\cos x\) and \(\sin x\) have same value at what \(x\)?

OpenStudy (anonymous):

thanku

OpenStudy (paxpolaris):

tanx =1 ... OR ... tanx =-1

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