Question

hello
i need help on solving this equation

Answer 1

\[\arcsin(x^2 -1)=x/3 \]

Answer 2

how to start that?

Answer 3

hmmmmm

Answer 4

sin inverse take value between -1 and 1

Answer 5

-1<=x^2-1<=1

Answer 6

can u solve it

Answer 7

i don't understand...i need some time to process what you wrote

Answer 8

x^2-1>=-1 means x^2>=0.......x is real number can be any thing
and x^2-1<=1 means \[x^2 >=2\]

Answer 9

\[-\sqrt{2}<=x<=\sqrt{2}\]

Answer 10

arcsin what value it can take ????

Answer 11

arcsin(y)
what could be the possible values of y???

Answer 12

-pi/2 and pi/2

Answer 13

no that is what we will get from arc sin

Answer 14

sin can take -pi/2 to pi/2

Answer 15

we can insert min -1 and max 1

Answer 16

-1<= y <=1

Answer 17

got something???

Answer 18

why you got an interval as solution?
the solution must be just one value