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Solve the system. 5(x-1)=29-3(y+2) 4(x+2)-22=3(2-y) (x,y) = ( , ) Suppose to use the elimination or substitution method but i cant figure it out please help thx
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you'll find its easier if you rearranged the equations into the form ax + by = c
5x-5=29-3y+6 5x+3y=40 Right?
nearly its - 6 n first line
4x+8-22=6-3y 4x+3y=20
it comes to 5x + 3y = 28
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ok so 5x+3y=28 4x+3y=20
right elimination method is quite easy just subtract and you;ve eliminated y
5x+3y=28 -4x-3y=-20 -4x=8 x=-2?
y=-4?
- and got x straight away
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What?
whys multiply by -1? you've got 3y in each equation 3y-3y = 0
so x=8?
yes simple
now plug x=8 into any of the equations to get y
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y=4
no try again
wrong sign
-4
4(8) + 3y = 20 3y = 20-32 = -12 y = -4
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thx :DDDDD
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