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(X^2-x-4)^(3/4)-2=6
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Add 2 to both sides. Raise both sides to the power 4/3. What do you get?
{-4,5}
@aum
correct
good job!
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(X^2-x-4)^(3/4)-2 I was going to finish the rest of my work but thank you!
I have been having the worst time solving this problem X^-2-x^-1-20=0 I guess the negative exponents are throwing me off
think of negative = 1/positive when doing exponents
x^-1 = 1/x
Okay I think this is how it should be rewritten yet I find myself being confused even more 1/x^2- 1/x-20=0
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