Question

Find the absolute extrema of the function on the closed interval.
f(x) = x^3 − 3/2x2, [−5, 6]

i got (-5,-200) for the min
and (6,162) for the max

i know the max is correct, but i'm not sure about the min.
please help

Answer 1

Well, f(-5) is not -200. That's first.
Clearly, f(-5) is the minimum.

Answer 2

i've just reworked the problem and got (-5,-162.5) as the min