Find the absolute extrema of the function on the closed interval.
f(x) = x^3 − 3/2x2, [−5, 6]

i got (-5,-200) for the min
and (6,162) for the max

i know the max is correct, but i'm not sure about the min.
please help

Question

Find the absolute extrema of the function on the closed interval.
f(x) = x^3 − 3/2x2,    [−5, 6]

i got (-5,-200) for the min
and (6,162) for the max

i know the max is correct, but i'm not sure about the min.
please help

tkhunny · Answer

Well, f(-5) is not -200.  That's first.
Clearly, f(-5) is the minimum.

anonymous · Answer

i've just reworked the problem and got (-5,-162.5) as the min