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Sketch the graph: f(x) = 5x^2 + 1 How do you solve to be able to sketch it?
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@LeightnerRach y = 5x^2 + 1
for any value of x y >0 when x = 0 y = 1
well the curve is a parabola that is always positive and has a y-intercept of y = 1 the line of symmetry is the y-axis so a sketch is simply |dw:1412042551714:dw| you could use a table of values x = -3, -2, -1, 0, 1, 2, 3, subsitute them plot the ordered pairs and then draw a line though them
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