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The function f is defined by f:x = 2x^2−12x+13 for 0≤x≤A,where A is a constant. i) State the value of A for which the graph of y = f(x) has a line of symmetry. ii) When A has this value, find the range of f.
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Why is the A so high up?
Supposedly A =6
Please explain more.
Anyways, I got it already. What about the next ques?
Substitue 6 into the equation. Hence 13 right? and -5 comes from the a(x+b)2+c equation right?
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Okok. Thanks. I grasp it already. Your explanation is too lengthy.
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