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Let the first number be \(\Large\rm x\). The number that comes after that would be \(\Large x+1\). The sum of these two consecutive numbers is \(\Large\rm 73\). \(\Large\rm x+x+1=73\) Just need a single step to match one of your option from this point :) Combine like-terms!
yay good job \c:/
\(\Large\rm .02x+.04(x+800)=92\) This equation represents our interest ^ 2% of the amount x, 4% of the amount x+800, and it sums up to 92 dollars of interest. Solving this equation gives us, \(\Large\rm x=1000\). Which tells us the amount in the other account would be, \(\Large\rm x+800=1800\). Yay good job \c:/
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