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Calculus1 10 Online
OpenStudy (anonymous):

A ball is thrown straight down from the top of a 300-ft building with an initial velocity of -12ft per second. The position function is s(t)=-16t^2+v0t+s0. What is the velocity of the ball after 4 seconds?

OpenStudy (aum):

Take the derivative of the position function to get the velocity function. put t = 4 and find v.

OpenStudy (aum):

s'(4) = ?

OpenStudy (anonymous):

s'(t)=-32t+v0 is that the derivative?

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