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Mathematics 15 Online
OpenStudy (anonymous):

@TheWaffleMan149

OpenStudy (anonymous):

OpenStudy (anonymous):

can you please help?

OpenStudy (anonymous):

The function is discontinuous when it has a vertical asymptote

OpenStudy (anonymous):

And to find where those are, you set the denominator equal to zero, and factor it

OpenStudy (anonymous):

So in this case, you have x^2-5x+4

OpenStudy (anonymous):

(x-4)(x-1)

OpenStudy (anonymous):

And now what?

OpenStudy (anonymous):

ohh so my answer is just 4,1 (:

OpenStudy (anonymous):

If it is set equal to 0

OpenStudy (anonymous):

Yep!!!

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