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integral of sqrt(1+cos6x)
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sort=sqrt?
sqrt
rewrite cos(6x) using double angle identity first
we should be able to write the inside as a perfect square :)
sqrt(1 + cos(6x)) = 2 cos^2 (3x)
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sqrt(1 + cos(6x)) = sqrt(2) | cos(3x) | this can be tricky
you can consider both cases separately usually it is fine with the instructor or in my experience if you consider one case (but they like for you to say which one)
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