A volume of 80.0mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the KOH solution if 25.7mL of 1.50 M H2SO4 was needed? The equation is 2KOH(aq)+H2SO4(aq)→K2SO4(aq)+2H2O(l)

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micahm · Answer

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aaronq · Answer

Find moles of acid

Write a ratio relating the moles of acid and base with their coefficients

Solve for moles of base

Find molarity of base given the volume