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write in exponential form
Rules you need to know:\[\sqrt[a]{x^b}=x^{\frac{b}{a}}\\~\\\dfrac{1}{x^n} = x^{-n}\]
i got \[\frac{ 8 }{ x ^{-1/7} }\]
\[{8\over \sqrt[7]{x^{15}}} \]\[={8\over x^{15/7}} \]\[=\large\color{green}{8\cdot x^{-15/7}} \]
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