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WILL GIVE MEDALS! The width of a rectangle is 6 in. less than its length. The perimeter is 68 in. What is the width of the rectangle?
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let the length = l in then the width w=l-6 in then use the perimeter rule for a rectangle
i got 14, but then i did it again and got 11!
1-6=-5
let x= length, y= width then, y=x-6 eq1 and for the perimeter we have 2x+2y=68 eq2 Two equations and two unknowns, perfectly solvable system. My suggestion would be to substitute equation 1 into 2 and solve for x, then use equation 1 again to solve for y
it is 14, i got it right! Thanks both of you :)
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