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Determine thru the Integral Test if the following converges or diverges.
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\[\frac{ 1 }{ \sqrt{x}(\sqrt{x}+1) }\]
if its a product in the denominator, yeah, but not sure thatll work for integration
can you determine a suitable u sub perchance?
I am lost.
lost at what?
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On how to integrate this.
if we let u = sqrt(x)+1, then du = 1/[2sqrt(x)] dx for a substitution
\[\int\frac{2}{u}du\]
when x=0, u=1 ... so \[\int_{1}^{\infty }\frac{2}{u}du\]
Ok i see that
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How did you arrive at 2/u du?
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