12/x-6+x=3+8x/x-6
what the hell am i doing with this equation it says what are the real roots of this equation the answer is x=15 and x=2 but how do i get this answer

Question

12/x-6+x=3+8x/x-6 
what the hell am i doing with this equation it says what are the real roots of this equation the answer is x=15 and x=2 but how do i get this answer

anonymous · Answer

you are trying to solve for the values of x that make the equation true (i.e. both sides are the same when you plug in x = 15 and x = 2.

What they mean by real is not imaginary....  when you take the square root of a negative, for example, the answer is imaginary.  We are only looking for real answers here.

anonymous · Answer

so when plugging the answers back in how would i solve this @piglet9

anonymous · Answer

technically you don't know these answers (pretend you didnt look at the answers)...

how would you simplify these equations...

anonymous · Answer

plug in 15 for the x values and 2 for the x values