Question

An equation of the line tangent to the graph of y equals x(two minus x) ^3 at the point (1,1) is

Answer 1

\[y=x(2-x)^3\]

Answer 2

your first step is to differentiate that

Answer 3

\[y-f(a)=f'(a ) \cdot (x-a)\]
tangent line will be this at x=a