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Show that AC= 4 sec(theta) + 5 csc (theta) Diagram below: http://imageshack.com/a/img537/1198/rfeIBl.png
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Hey Henry I'm assuming Tirayr told you about this website too.\[\sin^{-1} =5/BC\]
which turns out to be\[\csc \theta=BC/5\]
You get BC=csctheta x 5
and you do the same for the little triangle in the top left because the angles are equal and you get AB= 4 x sec theta
and then you add them to get AC
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Yep, it was Tirayr.
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