Find the linear and power function of lines passing through the points: (-3,19683) and (4,-147456)
\(y=mx+b\) gives a "linear" curve. Use the points to figure out what \(m\) and \(b\) are. Do you know how to do this?
What is the slope \(m\) of the line passing through the two points?
yes y2-y1/x2-x1
Im having trouble with the power function part
what is the form of a power function?
I don't know...I wasn't in lecture when it was taught..
The form is \(y=ax^b\), so we need to figure out what \(a\) and \(b\) are. For this we do something similar to finding the solution to a system of linear equations (the addition method) but its more like a division method use the two points and we get \(19683=a(-3)^b\) and \(-147456=a(4)^b\) Do you see how I came up with that?
yes
how do we find b?
solve for a in one equation, then plug that back in for a in the other equation
make sense?
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