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f(x)=2x^3-3x^2+1 i graphed the function and the derivative. a)use the graph to determine the exact point(s) where f has a horizontal tangent line. b)give the values of f'(x) at each of the points fount in part a
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the tangent is horizontal when the slope is 0, thus at the peaks and troughs
if there is a horizontal tangent then the slope of the tangent is 0, thus f'(x)=0
right. I got that there is a HA at (0,1) and (1,0)?
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