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f(x)=2x^3-3x^2+1 i graphed the function and the derivative. a)use the graph to determine the exact point(s) where f has a horizontal tangent line. b)give the values of f'(x) at each of the points found in part a
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they would be zero
what about part b
that is part b the tangent lines are horizontal where the derivative is zero
what about a) i got that the points were (0,1) and (1,0).. is that right?
i don't know but it is easier to do the second part first find the zeros of the derivative (easy as it is a quadratic)and that will tell you the x values of the horizontal tangents
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i think i did i answered them backwards
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