Question

How to solve this linear equation: t'-t=1+x

Answer 1

@ganeshie8 @phi

Answer 2

find the integrating factor and work the standard method ?

Answer 3

So the integrating factor is e^-x, right? Can you show the work?

Answer 4

\[\large (ye^{-x})' = (1+x)e^{-x}\]

integrating gives you

\[\large ye^{-x} = \int (1+x)e^{-x}~dx\]

Answer 5

use by parts to evaluate the right side integral

Answer 6

How did you get the (ye^-x)'?

Answer 7

Ahh replace y by t
it has to be t

Answer 8

\[\large te^{-x} = \int (1+x)e^{-x}~dx\]

Answer 9

Yes, I got it.

Answer 10

Also, do you know the prerequisite of Advanced Engineering Mathematics?

Answer 11

@SithsAndGiggles

Answer 12

I wouldn't know, I'm not an engineer...

Answer 13

That's fine.