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How to solve this linear equation: t'-t=1+x
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@ganeshie8 @phi
find the integrating factor and work the standard method ?
So the integrating factor is e^-x, right? Can you show the work?
\[\large (ye^{-x})' = (1+x)e^{-x}\] integrating gives you \[\large ye^{-x} = \int (1+x)e^{-x}~dx\]
use by parts to evaluate the right side integral
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How did you get the (ye^-x)'?
Ahh replace y by t it has to be t
\[\large te^{-x} = \int (1+x)e^{-x}~dx\]
Yes, I got it.
Also, do you know the prerequisite of Advanced Engineering Mathematics?
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@SithsAndGiggles
I wouldn't know, I'm not an engineer...
That's fine.
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