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Mathematics 21 Online
OpenStudy (anonymous):

A survey revealed that 31% of people are entertained by reading books, 39% are entertained by watching TV, and 30% are entertained by both books and TV. What is the probability that a person will be entertained by either books or TV?

OpenStudy (amistre64):

any thoughts about it?

OpenStudy (anonymous):

I was thinking I had to add .31 and .39?

OpenStudy (amistre64):

well, thats part of it, i was thinking more of the formula thats associated with it

OpenStudy (amistre64):

P(AorB) = P(A) + P(B) - P(AandB)

OpenStudy (anonymous):

In this case, It should be 40%

OpenStudy (anonymous):

Ok thank you that's what I had

OpenStudy (amistre64):

goo dluck

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