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evaluate the integral (36dx/36+e^x)
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k * integrate (k+e^x)^(-1) have you tried by parts?
ln(k+e^x) e^x+k-k k --------- = 1 - ----- k+e^x k+e^x so if we add 1 and subtract 1, we should be able to work this
\[\int\limits \frac{ 36 dx }{ 36+e^x }=\int\limits \frac{ 36+e^x-e^x }{ 36+e^x }dx=\int\limits 1dx-\int\limits \frac{ e^x }{ 36+e^x } dx=?\]
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