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OpenStudy (anonymous):
The expression ( cot^2x/1-sin^2x is equivalent to ??
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OpenStudy (tkhunny):
You have not written what you intend. Please remember your Order of Operations and use parentheses where necessary.
OpenStudy (anonymous):
cot^2x/ 1-sin^2x
OpenStudy (anonymous):
sorry there's no parentheses in the question
OpenStudy (tkhunny):
No, try cot^2x/ ( 1-sin^2x ).
It is not the same in print as it is inline. You must see the difference and compensate.
OpenStudy (tkhunny):
Change cotangent to cos(x) / sin(x)
and change 1-sin^2(x) to cos^2(x)
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OpenStudy (anonymous):
what should I do after that ? please help
OpenStudy (tkhunny):
Did you do it? \(\dfrac{\cos^{2}(x)}{\sin^{2}(x)}\cdot \dfrac{1}{\cos^{2}(x)}\)
Are you sure you can't come up with something?
OpenStudy (anonymous):
I got you :) Thank you sooo much
OpenStudy (anonymous):
I did it wrong the first time
OpenStudy (tkhunny):
Rule of thumb -- If you don't see it right away, change it to sine and cosine and hope...
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OpenStudy (anonymous):
I'll remember that rule
OpenStudy (tkhunny):
Don't forget the "hope" part. There is always hope! :-)
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