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Someone check my work please? (ew algebra review) What is the value of x in the equation \(\frac{2}{x}\)-3=\(\frac{26}{x}\)
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\(\Large\frac{2}{x}\)-3=\(\Large\frac{26}{x}\) -2/x -2/x ----------- -3=\(\Large\frac{26}{x}\)-\(\Large\frac{2}{x}\) (\(\Large\frac{1}{24}\))-3=\(\Large\frac{24}{x}\)(\(\Large\frac{1}{24}\)) x= -\(\Large\frac{1}{8}\)
you should have \[\Large \frac{1}{x} = -\frac{1}{8}\]
I'm sure you see how to solve for x from here
oh i see! knew something wasn't right, thanks!
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