Question

2[(2y−1)+y]≤5(y+3)
can someone help me solve this

Answer 1

distribute first of all
\[6y -2 \le 5y +15\]
then combine like terms
6y -5y = y
15+2 = 17
\[y \le 17\]

Answer 2

idk the order to distribte in original equation like what side to start on

Answer 3

well right side is easy left side i dont understand

Answer 4

ignore the parenthesis around "2y-1"

---> 2( 2y -1 +y) = 4y +2 +2y = 6y + 2

Answer 5

ok thx easy now