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Mathematics 24 Online
OpenStudy (anonymous):

differentiate with respect to x x sin (3x)

OpenStudy (anonymous):

So here you have a product of two terms (x) and sin3x so you need to use the product rule

OpenStudy (anonymous):

\[dx/dy(x) (\sin3x) + x (dy/dx(\sin3x))\]

OpenStudy (anonymous):

=1xsin3x + x(cos3x)x3

OpenStudy (anonymous):

you there?

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