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OpenStudy (anonymous):
differentiate with respect to x x sin (3x)
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OpenStudy (anonymous):
So here you have a product of two terms (x) and sin3x so you need to use the product rule
OpenStudy (anonymous):
\[dx/dy(x) (\sin3x) + x (dy/dx(\sin3x))\]
OpenStudy (anonymous):
=1xsin3x + x(cos3x)x3
OpenStudy (anonymous):
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