Question

(x^4 + 2 x i) -(3x^2+ iy) = (3-5i)+(1+2iy)
find x and y.
a) x = 2, y = 3
b) x = 3, y = 1/3
c) x = -2, y = -3
d) none of these

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Answer 1

add similar term

Answer 2

x^4+2xi-3x^2-iy

Answer 3

(x^4-3x^2)+i(2x-y)

Answer 4

in complex when number are compared than real part is compared with real and i with i

Answer 5

(x^4-3x^2)+i(2x-y)= (3-5i)+(1+2iy)
(x^4-3x^2)+i(2x-y)=3+1-5i+2iy
(x^4-3x^2)+i(2x-y)=4+i(-5+2y)

Answer 6

compare real with real and i with i now

Answer 7

x^4-3x^2=4

Answer 8

and
2x-y=-5+2y

Answer 9

solve these two to get your ans

Answer 10

its simple to solve now u can do it by yourself

Answer 11

ok how to solve further ?

Answer 12

2x-y=-5+2y
2x-3y=-5

Answer 13

x^4-3x^2=4
factorise this one

Answer 14

and put value of x from here in 2x-3y=-5

Answer 15

to get y

Answer 16

ok

Answer 17

x^4-3x^2=4
hint: let x^2=t

Answer 18

t^2-3t=4

Answer 19

t^2-3t-4=0

Answer 20

t^2-4t+t-4=0
t(t-4)+(t-4)=0
(t+1)(t-4)=0

Answer 21

and remember t=x^2
so whatever the value of t put it =x^2

Answer 22

t=-1 and t=4

Answer 23

x^2=-1 not possible it wont give you the negative value ...so cancel this solution

Answer 24

x^2=4

Answer 25

x=-2 or 2

Answer 26

now try further plzzz

Answer 27

thak you

Answer 28

welcm buddy :)