Question

8ln(2x)=5

Answer 1

what is the question

Answer 2

8ln(2x)=5

\[\ln(2x)^{8}=5\]

\[2x ^{8}=e ^{5}\]

\[x ^{8}=\frac{ e ^{5} }{ 2 }\]

\[x=\sqrt[8]{\frac{ e ^{5} }{ 2 }}\]

Is this right?

Answer 3

yes its right provided he/she wants the value of x

Answer 4

yeppppppp its damn right

Answer 5

The answer given by @Krokodzilla is not correct. Note:\[(2x)^8\ne2x^8\]

Answer 6

yes i didnt even notice that

Answer 7

But anything before a ln can be put as a power of whats in the ln right?