Question

x^2-x-9/x-3

Answer 1

factorise numerator

Answer 2

or divide directly

Answer 3

here division will be better as factor are not easy to do

Answer 4

You should first write it correctly.

x^2-x-9/x-3 means \(x^{2}-x-\dfrac{9}{x}-3\) and probably is not what you intend.

Try instead: (x^2-x-9)/(x-3) which means \(\dfrac{x^{2}-x-9}{x-3}\)

Good luck with the factoring...