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What is the largest possible value for the slopes of all tangent lines to the graph of y=-cos((2x)/3)?
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\[y=-\cos(\frac{ 2x }{ 3 })\]
my guess, is that when u take the derivative, u get \[y'=\frac{ 2\sin(\frac{ 2x }{ 3 }) }{ 3 }\]and that x should be
\[\frac{ 3\pi }{ 4 }\] however this is wrong
The question doesn't ask you for the value of \(x\) for which the thing is maximum. It asks you what the maximum is, which is 2/3.
oooo that makes sense, thank you
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