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Mathematics 7 Online
OpenStudy (anonymous):

Evaluate each expression for the given values of the variables -5(x+2y)+15(x+2y); x=7 and y =-7 -k^2-(3k-5n)+4n; k=-1 and n=-2

OpenStudy (jdoe0001):

\(\large { -5({\color{brown}{ x}}+2{\color{blue}{ y}})+15({\color{brown}{ x}}+2{\color{blue}{ y}})\quad \begin{cases} {\color{brown}{ x}}=7\\ {\color{blue}{ y}}=-7 \end{cases}\implies \square ? \\ \quad \\ -{\color{brown}{ k}}^2-(3{\color{brown}{ k}}-5{\color{blue}{ n}})+4{\color{blue}{ n}}\quad \begin{cases} {\color{brown}{ k}}=-1\\ {\color{blue}{ n}}=-2 \end{cases}\implies \square ? }\)

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