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Mathematics 7 Online
OpenStudy (anonymous):

How do I go about to approach this vector theorem? I will attach the image.

OpenStudy (anonymous):

OpenStudy (amistre64):

well, what does it mean to be parallel to a plane?

OpenStudy (amistre64):

would you agree that the xz plane has a constant y value at y=0? if so, then what property would a parallel plane have?

OpenStudy (amistre64):

wait, mighta read the question to fast

OpenStudy (amistre64):

think of a curve that is equidistant from the origin and the x aixs

OpenStudy (amistre64):

let the vector u be defined by (a,b,c) then y = |u| for all vectors u

OpenStudy (amistre64):

p = (a,sqrt(a^2+b^2+c^2),c) |dw:1412559566251:dw|

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