Question

n^2=[n(n+1)(2n+1)/6]

Answer 1

What is the question? Solve for n ?

Answer 2

That right hand side looks like \[\sum_{i=1}^{n}i^2=\frac{n(n+1)(2n+1)}{6}\]

Answer 3

maybe it is an induction problem?

Answer 4

Like:
Prove that equality I just mentioned for integer n>=1.