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for f(x)=10^-x, if x--> negative infinity what is x
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for f(x)=10^-x, evaluate if x--> negative infinity
\[f(x)=1/10^{x}\] If x<0 then the fraction flips and becomes \[10^{x}\]
Well idk if ilr1 is right but I'm thinking there is something to do with a restriction being in the denominator.
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