Factor completely 2x3 + x2 - 18x – 9.

(x2 - 9)(2x + 1)

(x - 3)(x + 3)(2x - 1)

(x - 3)(x + 3)(2x + 1)

(2x - 3)(2x + 3)(x - 1)

Question

Factor completely 2x3 + x2 - 18x – 9.

 (x2 - 9)(2x + 1)

 (x - 3)(x + 3)(2x - 1)

 (x - 3)(x + 3)(2x + 1)

 (2x - 3)(2x + 3)(x - 1)

anonymous · Answer

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anonymous · Answer

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anonymous · Answer

is that the choices on the bottom

anonymous · Answer

yeah right below the questions are the answer choises

anonymous · Answer

ok hold on

anonymous · Answer

(x - 3)(x + 3)(2x + 1)

anonymous · Answer

did that help because that's the answere

andrewkaiser333 · Answer

hey wants to know how you did it

andrewkaiser333 · Answer

sorry been 4 years since i did this but i remember you had to use foil sorry bro

zpupster · Answer

2x3 +x2- 18x - 9

do it in parts

(2x3+x2) factor out the x2
x2(2x + 1)

then
(-18x-9) factor out the -9
-9(2x+1)    so

(x2-9)(2x+1)

we recognize that (x2-9) is the differnce of 2 squares, x and 9
the middle terms +3x and -3x cancel

so 

(x-3)(x+3)(2x+1)

that is one way to do these