Medal and Fan for whoever answers

A painting company charges $250 base plus $16 per hour. Another painting company charger $210 base plus $18 per hour. How long is a job for which the two companies costs are the same?

Question

Medal and Fan for whoever answers

A painting company charges $250 base plus $16 per hour. Another painting company charger $210 base plus $18 per hour. How long is a job for which the two companies costs are the same?

anonymous · Answer

Just solve the equation 
$$250+16x=210+18x$$ for $$x$$

akashdeepdeb · Answer

Let 't' be the number of hours.

Company A : 250 + 16t
Company B : 210 + 18t

Now, for the charges to be same, equate them! 

250 + 16t = 210 + 18t
2t = 40
t = 20 hours

Getting this? :D

anonymous · Answer

Yep thanks @AkashdeepDeb