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find the vertex , axis of symmetry, domain and range for the graph of y=o.1(x-3.2)^2
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What is that little o. in front of the 1 there?
I think it's supposed to be a 0.1 and it didn't quite make it there. But even still, the standard form of a vertex equation for this quadratic which happens to be a parabola, is this:|dw:1412632683472:dw|
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