Question

Evaluate the difference quotient for the given function.

Answer 1

whatzz the comment

Answer 2

so the problem looks like, \[f(x) = 4 +3x - x^2, \frac{ f(3+h)-f(3) }{ h}\]

Answer 3

f(3)=4+3*3-3^9=4+9-9=4
f(3)=4
f(3+h)=4+3*(3+h)-(3+h)^2
=4+9+3h-(3^2+h^2+2*3*h)
=4=9+3h-9-h^2-6h
=4+9-9+3h-6h-h^2=4-3h-h^2

Answer 4

put value of f(3)and f(3+h) there

Answer 5

\[\frac{ 4-3h-h^2-4 }{ h }=\frac{ -3h-h^2 }{ h }=\frac{ h*(-3-h)}{h}=-3-h\]