Question

Find the area of the region

Answer 1

y = x^2 - 2x
y = x

Answer 2

I have the graph drawn and found the bounds
\[\int\limits_{0}^{3} (x^2- 2x) - (x)\]

Answer 3

When I solve for the area, I get -9/2. The answer is 9/2. Am I doing something wrong? or is this just one of those things that happens

Answer 4

You're just upside down. Try x - (x^2 - 2x).

List the greater, first.

Answer 5

Oh wow thanks, I originally tried that, but I just noticed i forgot to distribute the negative