I'm confused with a couple problems I want to answer before a test in an hour. How do you solve 81-1x4 the is squared...

Question

aum · Answer

question not clear.  1x^4 ?   
"the is squared" ??

aum · Answer

Can you post a screenshot of the question?

anonymous · Answer

$$81-1x^{4}$$

anonymous · Answer

$$81-1x ^{4}$$ Could you help me with it?

aum · Answer

Solving requires an equation.  There is no equation here.
We can factor it if that is what is asked.  But since you are not posting the full question it is hard to answer the question.

anonymous · Answer

Sorry it is factoring, im not sure how to break it down.

aum · Answer

I will assume they are asking you to factor it:
$$
81 - 1x^4 = 81 - x^4 = 9^2 - (x^2)^2 = (9+x^2)(9-x^2) \
9 - x^2 = 3^2 - x^2 = (3 + x)(3-x) \
81 - 1x^4 = (9+x^2)(9-x^2) = (9+x^2)(3+x)(3-x)
$$

aum · Answer

$a^2-b^2 = (a+b)(a-b) $

anonymous · Answer

One more problem and that was $$1x ^{3}+64$$ If you do not mind helping..

aum · Answer

$$\large 
a^3 + b^3 = (a+b)(a^2 - ab + b^2) \ \large
1x^3 + 64 = x^3 + 64 = x^3 + 4^3 = (x+4)(x^2 - 4x + 16)
$$

anonymous · Answer

thank you it is really appreciated!!!

aum · Answer

You are welcome.