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OpenStudy (anonymous):
rx+9/5=h for x
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Elsa213 (elsa213):
rx+(9/5)=h rx=h-(9/5) x=(h-(9/5))/r
OpenStudy (anonymous):
where is the h- coming from
Elsa213 (elsa213):
from ur question
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OpenStudy (anonymous):
heres what I did rx+9/5=h rx+9/r=5h/r x+9=5h/r x=9-9=5h-9/r x=5h-9/r
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